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How do I solve for x here: ln(4x)=y
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Wait, is "In" part of the equation?
yes
Well, basically you have to solve the equation by rewriting in exponential form using the definition of a logarithm and simplifying. Would you like me to help you through the process?
Yes please. It's been a while since I worked with logarithms and stuff. This is actually part of a calculus volume problem. I want to integrate in terms of y.
Alright, well basically the definition of a natural logarithm states that e^y=x if and only if ln x=y
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So, because of this, you're able to convert it to \[4x=e^y\]
After that, you simply divide each side by four, after that, let me know what you got.
\[x=\frac{ e^y }{ 4 }\]
You're the bomb man, that's correct. Nice work!
yay! :D
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thanks
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