I need help with some trig for geometry!
What's your question?
It has to do with triangles and stuff. Hold on I'll attach a pic.
Are you looking for the two angles, the third side, the area, or what?
1.Find the following and show all work including the trigonometric ratios used: A.The measure of angle A B.The measure of angle B C.The length of side AC Angle C is 90 degrees
Let's start with the side. Have you heard of the Pythagorean Theorem?
Yes I have, but to be honest I'm no good at it
\[a^2+b^2=c^2\]
Plug in the two sides you already know as a and b.
Do you have that?
Well the only sides labeled in my pic say 10 and 4. It doesn't say which is side A or B
That doesn't matter, though. a+b=b+a so the numbers are interchangeable. Just plug the digits in.
Ok. So: 10^2+4^2=C^2
\[10^2=100\]\[4^2=16\]\[16+100=116\]\[116=c^2\]
\[\sqrt{c}=116\]
I can't delete that. \[\sqrt{116}=c\]
What's the square root of 116?
I just did it on my calculator. It's 10.77
So now we have this:|dw:1465698024021:dw|
"c" in this formula is always, always, always the one across from the right angle, so c=10.
something is off. Usually when the largest side of the triangle (hypotenuse) is given we have to find a side that's smaller than what the hypotenuse is. Since we were given 4 and 10, one of the sides has to be between that value
correct mjdennis
My apologies, I was paying attention to the values rather than the placement!
I understand, it's all good:) So 10.77 is the length of side C. I think I can solve the other questions now. I do have one more triangle though... Are you guys able to help me with that?
our correct version is supposed to be |dw:1465698223169:dw|
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