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Mathematics 20 Online
OpenStudy (chizzy):

A chemistry student mixes two solutions to study the properties of the resulting mixture. The temperature of the new solution is given by the function T = 24t − 2t2 + 5, where T is the temperature in degrees Celsius and t is the time elapsed in seconds after the solutions are mixed. What is the time interval that the temperature of the solution will be at least 69°C?

OpenStudy (welshfella):

substituting for T 69 = 24t - 2t^2 + 5 can you solve this ?

OpenStudy (welshfella):

its a quadratic equation so we need 0 on one side : -2x^2 + 24t - 64 = 0 to make it simpler divide through by -2 x^2 - 12t + 32 = 0 the solutions of this equation will give you the times when T = 69

OpenStudy (welshfella):

in the original equation we had -2t^2 so the graph will be a parabola which opens downwards and will have a maximum value of temperature. The time between the 2 roots is what you require

OpenStudy (welshfella):

can you solve the equation?

OpenStudy (welshfella):

any ideas?

OpenStudy (welshfella):

x^2 - 12x + 32 this will factor you need 2 numbers whose product is +32 and whose sum is -12. can you think of these 2 numbers?

OpenStudy (welshfella):

Have you studied these equations?

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