Question

~*~``BECOME FAN && MEDAL && TESTIMONIAL``~*~
Use the discriminant to find the number of real solutions of the equation 3x^2 – 5x + 4 = 0. Show your work.

Answer 1

do you know how to find discriminant?

Answer 2

nope :(

Answer 3

This equation is of form ax^2+bx+c=0
a = 3 b = -5 c = 4
x= [-b+/-sq. (b^2-4ac)]/2a]
x= [5 +/-sq. (-5^2-4(3)(4)]/(2)(3)
Discriminant is b^2-4ac = -23

Answer 4

@*Poker-Face* ???

Answer 5

yes correct
the discriminant is -23

Answer 6

whenever the discriminant is negative
it implies that the equation has no real roots

Answer 7

Okay thx :)

Answer 8

np (: