Suppose a line has slope -2/3
and passes through the point (1, 8). Which other point must also be on the graph?
A) (7, 4)
B) (7, 12)
C) (-5, 4)
D) (-5, -12)

Question

Suppose a line has slope -2/3
 and passes through the point (1, 8). Which other point must also be on the graph?
A)	(7, 4)	
B)	(7, 12)	
C)	(-5, 4)	
D)	(-5, -12)

heart_offire · Answer

@jim_thompson5910

photon336 · Answer

you can use the point slope formula

heart_offire · Answer

ok but dont i need two sets of points instead of one

photon336 · Answer

not necessarily all you need is the slope of the line and one of the points that you want it to go through 

$$m(x-x_{0}) = (y-y_{0})$$

where m  = -2/3 
and 

x0,y0 = (1,8)

$$\frac{ -2 }{ 3 }(x-1) = (y-8)$$

photon336 · Answer

now simplify the equation

heart_offire · Answer

@Photon336 i got B

photon336 · Answer

how did you get that ? also first simply the equation above

heart_offire · Answer

im kindve confused on simplifying, i turned the fraction into a decimal

satellite73 · Answer

slope of $-\frac{2}{3}$ means right three , down two

satellite73 · Answer

so from $(1,8)$ right three down two takes you to $(4,5)$ 
you can find the others that way

satellite73 · Answer

ok actually that was wrong'
from $(1,8)$ right three down two goes to $(4,6)$

satellite73 · Answer

go right another three ,down another two
where do you end up /

heart_offire · Answer

umm 7,4

satellite73 · Answer

um yeah

heart_offire · Answer

oh ok so what next

satellite73 · Answer

that was all the question asked right?  what other point is on the line

heart_offire · Answer

oh ok

heart_offire · Answer

thanks