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Find the length of the midsegment. 15 22 44 13
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The midsegment (5x+2) is exactly half as long as the parallel side (3x+32) So this means \[\Large \frac{1}{2}*(3x+32) = 5x+2\] \[\Large 3x+32 = 2*(5x+2)\] \[\Large 3x+32 = 10x+4\] keep going to solve for x
once you know what x is, use it to compute 5x+2
22
@jim_thompson5910
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yep it's 22
nice work
thanks at first I put 15 because in both equations it would equal 77
If M∠J=66, m∠L=64, and m∠K=50, list the sides of ΔJLK in order from smallest to largest
Rule: the largest angle is always opposite the largest side Rule: the smallest angle is always opposite the smallest side
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