HELP? The diagram shows a section of a bridge between the points A and K. The length of line segment AK is 640 meters. ∆ABC, ∆CDF, and ∆FJK are similar, and 2AC = CF = 2FK. The first pillar BG , is 20 meters tall. The area of ∆CDF is ____ square meters.
@Bigbosssaint21
@jigglypuff314
In geometry, drawing the diagram and filling all given information is the best first step. I'll help you get started by showing a diagram everyone can see. Please complete the diagram by showing all pertinent information given in the question. |dw:1465921361288:dw|
i dont understand what you want me to do
how do i find the length
It will help you solve a geometry (or trigo) problem if you show all given information on the diagram. Otherwise the problem will look difficult. I'll do the first step: "The length of line segment AK is 640 meters." so |dw:1465921533408:dw| Please continue reading the question and put all information on the diagram. After that, you can start solving the problem.
CF = 40?
@jigglypuff314
@jim_thompson5910
@pooja195
@ganeshie8
@mjdennis
What three thins add up to AK?
you can find the lengths of AC , CF and FK by forming an equation AC + CF +FK = 640 you also know that 2AC = CF = 2FK so you can find the lengths of these 3
As all the triangles are similar you can then find the length of the pillar DH and the area of triangle CDF.
if we let length of AC = x then CF = 2x and FK = x so x + 2x + x = 640 solve for x
is there a formula
can you solve the above for x?
im not sure how because there is only 2 given numbers
what is x + 2x + x equal to?
640
what I mean is simplify x + 2x + x
we are trying to solve the equation - find value of x
whats the first step in finding x
- simplifying x + 2x + x
so x will be just 1 number right
yea
180?
160?
4x = 640 x = 640/4 = 160
so the area of CDF is 160?
No 160 is the length of AC and FK and CF = 2*160 = 320.
oh alright! so thats the answer? 320?
No we are asked for the area of the triangle CDF the triangles are similar so as i explained earlier we can now find the height of triangle CDF (DH)
would the height be 40?
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