Question

Check my work -

How to find the eccentricity of the following eclipse?

(x+2)^2/12 + (y-4)^2/9 = 1

Answer 1

The equation eccentricity is sqrt(1-b^2/a^2

Correct?

So, this stands to reason that it's -

sqrt(1-9^2/12^2)

Answer 2

\[b^2=a^2\left( 1-e^2 \right),1-e^2=\frac{ b^2 }{ a^2 },e^2=1-\frac{ b^2 }{ a^2 },e=\sqrt{1-\frac{ b^2 }{ a^2 }}\]
so you are absolutely correct.

Answer 3

correction
\[a^2=12\]
b^2=9
so correct accordingly and show again.