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OpenStudy (rowanwhitethorn):
OpenStudy (kgrendel0324):
Do you know the formula?
OpenStudy (rowanwhitethorn):
yes
OpenStudy (kgrendel0324):
Okay. So you have the base measurement and the height.
Just plug it in.
OpenStudy (rowanwhitethorn):
I keep getting the wrong answer :/
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OpenStudy (kgrendel0324):
alright look.
volume= 1/3 (Bh)
B= area of base
h= height of cone
OpenStudy (rowanwhitethorn):
i got 210, which i know isn't correct.
OpenStudy (kgrendel0324):
hmm. thats what i got too. Why do you know it isnt correct?
OpenStudy (rowanwhitethorn):
Because the answer choices are
A. 10,390.8 in^3
B. 5,195.4 in^3
C. 3, 463. 6 in^3
D. 329.9 in^3
OpenStudy (kgrendel0324):
well. this is interesting. wait a minute.
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OpenStudy (kgrendel0324):
im just as stuck as u are...
OpenStudy (campbell_st):
the volume is the same as a normal cone
you just need the perpendicular height that is given in the question
OpenStudy (campbell_st):
well remember the formula is
\[V = \frac{1}{3} \times \pi r^2 \times h\]
so to get 210 I'd guess all you have done is
\[V = \frac{1}{3} \times 30 \times 21\]
OpenStudy (campbell_st):
the value of 21 is the diameter of the base of the cone and not the area of the base...
so havve the diameter to get a radius