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The equation of line xy is (y-3) = -2/3(x-4) what is the slope of a line perpendicular to xy -2 3 -2/3 3/2
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what is slope of given line?
Idk thats all the given info
-2/3
\[y-y _{1}=m \left( x-x _{1} \right)\]
slope of line perpendicular to this line is \[-\frac{ 1 }{ m }\]
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now can you tell me the slope of perpendicular line?
Didn't that guy already say the answer lol
no,he told only the slope of given line.
Hmm
Yeah the topic of slope is insanely confusing
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negative reciprocal. \[=-\frac{ 1 }{ \frac{ -2 }{ 3 } }=1*\frac{ 3 }{ 2 }=\frac{ 3 }{ 2 }\]
How would you solve after that?
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