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Mathematics 15 Online
OpenStudy (natasha18):

Sine Cosine and tangent help!! I did these problems and i was sure i was right but I keep missing them... Can you help me figure out what I did wrong???

OpenStudy (natasha18):

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OpenStudy (natasha18):

I had to find x

OpenStudy (natasha18):

and roundto the nearest tenth

OpenStudy (natasha18):

my second answer i got was 11.04

OpenStudy (natasha18):

is that right

OpenStudy (natasha18):

i dont wanna submit it until i know

OpenStudy (aaronandyson):

sin 34 = opp/hypo

OpenStudy (aaronandyson):

0.559 = 12/x x = 12/0.559

OpenStudy (natasha18):

oooh ok so 21.5

OpenStudy (aaronandyson):

looks good.

OpenStudy (natasha18):

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OpenStudy (natasha18):

solving for x i got 41.4 degs

OpenStudy (natasha18):

but i i think i know what ive been doing wRong

OpenStudy (aaronandyson):

What x do you need? tan x cos x or sin x?

OpenStudy (natasha18):

well i use sin bc we have the opp and hypo

OpenStudy (natasha18):

wait i got .7222... am i supposed to do inverse sin?

OpenStudy (aaronandyson):

Yes 0.722 is correct.

OpenStudy (aaronandyson):

So we know sin x = 0.722 therefore x = ?

OpenStudy (natasha18):

i got 41.4

OpenStudy (aaronandyson):

I got x = 46....

OpenStudy (natasha18):

wait it woul be 46.2

OpenStudy (natasha18):

yeah ok

OpenStudy (aaronandyson):

yes 46.2 should be good..

OpenStudy (natasha18):

how do you know when to use inverse???

OpenStudy (natasha18):

that confuses me

OpenStudy (aaronandyson):

\[\sin \theta = x\] \[\theta = \sin^{-1} x\]

OpenStudy (natasha18):

where does the theta come in... i dont really understand that part

OpenStudy (aaronandyson):

So say \[\sin 30 = \frac{ 1 }{ 2 }\] \[\theta = \sin^{-1} \frac{ 1 }{ 2 }\]

OpenStudy (aaronandyson):

so theta = 30

OpenStudy (natasha18):

why does theta equal 30?

OpenStudy (natasha18):

ooooh ok nvm i see it

OpenStudy (aaronandyson):

because sin 30 = 1/2

OpenStudy (natasha18):

itwas an example haha

OpenStudy (aaronandyson):

Yes. That was an example.

OpenStudy (natasha18):

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OpenStudy (natasha18):

i got 61.4

OpenStudy (aaronandyson):

Find hypo first.

OpenStudy (natasha18):

how do i do that?

OpenStudy (natasha18):

i set it up like tanX = 15/14

OpenStudy (aaronandyson):

Hypo = 15^2 + 14^2 then we take the square root of that answer.

OpenStudy (aaronandyson):

tan x = 15/14 is also good

OpenStudy (natasha18):

oooh duh pythagorean theorem lol

OpenStudy (natasha18):

soo do i need to find hypotenuse? or can i solve the problem w/o it?

OpenStudy (aaronandyson):

You can use tan X TO find it..

OpenStudy (natasha18):

ooooh

OpenStudy (natasha18):

ok i worked it out and got 47 degrees

OpenStudy (natasha18):

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OpenStudy (natasha18):

i got cosX = .8

OpenStudy (natasha18):

then i got 36.9 by arccos

OpenStudy (natasha18):

is that right?

OpenStudy (natasha18):

@Whitemonsterbunny17 hey u any good at trig?

OpenStudy (natasha18):

or @mathmate can you check my last one to see if its right?

OpenStudy (mathmate):

Yes, that is correct, well-done! :)

OpenStudy (natasha18):

thanks! one more?

OpenStudy (natasha18):

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