Question

In a carnival drawing, a green ticket wins $1, a yellow ticket wins $5, and a blue ticket wins $10. There are 100 green tickets, 25 yellow tickets and 5 blue tickets. In simplest form, what are the odds against winning less than $10?
A) 1:4
B) 1:5
C) 1:10
D) 1:25

Answer 1

Can you help me?

Answer 2

@sleepyjess

Answer 3

Just someone plz help meh!

Answer 4

@mathmate
@charleskelsey1
@ILovePuppiesLol

Answer 5

Steps:
1. find the probability P(10) of \(winning\) $10 (blue ticket)
2. find the probability P(others) of winning $1 or $5 (note: P(10)+P(others)=1, i.e. complementary.)
3. find the ratio of probabilities to get the odds.
Remember the
odds \(against\) winning "less than $10" is the same as
odds \(for\) winning "$10"
since
"less than $10" and "$10" are complementary in this problem.

Answer 6

@mathmate so it's 1:4?

Answer 7

That's what I got

Answer 8

What are the probabilities of winning $10 and that of less than $10?

Answer 9

hint:
Count the number of tickets are there, how many for $10 (blue) , how many are for less than $10 (yellow, green)?