Use the discriminant to find the number of real solutions of the equation
3x^2 – 5x + 4 = 0. Show your work.

This equation is of form ax^2+bx+c=0
a = 3 b = -5 c = 4
x= [-b+/-sq. (b^2-4ac)]/2a]
x= [5 +/-sq. (-5^2-4(3)(4)]/(2)(3)
Discriminant is b^2-4ac = -23

no real roots

Is this right?

Question

Use the discriminant to find the number of real solutions of the equation 
3x^2 – 5x  + 4 = 0. Show your work.

This equation is of form ax^2+bx+c=0 
a = 3 b = -5 c = 4 
x= [-b+/-sq. (b^2-4ac)]/2a] 
x= [5 +/-sq. (-5^2-4(3)(4)]/(2)(3) 
Discriminant is b^2-4ac = -23

no real roots

Is this right?

rishavraj · Answer

yup no real roots :)) 
@Needhelpp101

needhelpp101 · Answer

ty :)