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OpenStudy (mjdennis):
Haha, it is right there after the space!
OpenStudy (natasha18):
OpenStudy (natasha18):
haha XD
OpenStudy (natasha18):
i got 12/2 but im not sure if its right
OpenStudy (will.h):
explain your steps please
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OpenStudy (natasha18):
i know its an improper fraction
OpenStudy (will.h):
how did you get 12/2
OpenStudy (natasha18):
just a guess ;lol
OpenStudy (natasha18):
i sent you a screen shot of the question
OpenStudy (phi):
do you know about 30-60-90 triangles. what is the length of "x" ?
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OpenStudy (will.h):
phi is here, he will most def walk you through this, just use trigonometric functions , best of luck :)
OpenStudy (natasha18):
x 15/2
OpenStudy (phi):
yes. now notice x is the hypotenuse of the "small" triangle on the left
notice a is opposite the 30 degree angle. what is a ?
OpenStudy (pawanyadav):
a tan60°= b tan30°
do u get this equation?
OpenStudy (phi):
in other words, you have another 30-60-90 triangle with hypotenuse 15/2 (or 7.5)
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OpenStudy (natasha18):
@Pawanyadav so that would be A*1.7321 equals b*.5774
OpenStudy (mjdennis):
2 parts to work with: (1) remember from 'our' last problem, you can make a relationship between similar sides. (2) in a 30-60-90 triangle, one of the sides is half the hypotenuse. Do those help?
OpenStudy (pawanyadav):
Don't convert them in decimal
OpenStudy (natasha18):
\[\cos60=\frac{ a }{ \frac{ 15 }{ 2} }\]
OpenStudy (natasha18):
would that be a correct way of solving it??
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OpenStudy (pawanyadav):
Just keep them in under root
As. a(√3)= b/(√3)
means 3 a= b
OpenStudy (pawanyadav):
Now. use information given in question..
a+b=15
a+3a=15
4a=15
a=15/4
OpenStudy (mjdennis):
There are lots of ways for this one. I used the results of that other problem: a/x = x/(a+b), and x=(a+b)/2. I remember you saying you are working a section involving similar triangles, so I am trying to keep it in that context..
OpenStudy (natasha18):
can you help me find z??
OpenStudy (pawanyadav):
Z ?????
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OpenStudy (natasha18):
in the diagram
OpenStudy (natasha18):
oh wait nvm i can find that using the pythagorean theorem
OpenStudy (pawanyadav):
Yes first u have to find y.
OpenStudy (natasha18):
how do i do that?
OpenStudy (pawanyadav):
tan60° =?
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OpenStudy (natasha18):
wouldn't i use pythagoream theorem??
OpenStudy (natasha18):
bc i already know x and a
OpenStudy (pawanyadav):
What are u getting?
OpenStudy (natasha18):
well i know \[x^2=a^2 + y^2\]
OpenStudy (pawanyadav):
Do u know x.
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OpenStudy (natasha18):
7.5
OpenStudy (pawanyadav):
If u know x , u can direct use
x2 + z2=225
OpenStudy (natasha18):
z2 is 168.75
OpenStudy (will.h):
you guys still working on this? wow
OpenStudy (natasha18):
im not sure but the answer has to fit in the format below
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OpenStudy (natasha18):
so it cant be in decimal form
OpenStudy (pawanyadav):
So it should be (15√3)/2
OpenStudy (natasha18):
well thats the answer i got for y... so whats y?
OpenStudy (pawanyadav):
Use a2+y2=x2
OpenStudy (pawanyadav):
Or y=a tan60°
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