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Average value of functions
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Number 22
\[\frac{ 1 }{ 3 }\int\limits_{1}^{4}f(x)=5\]
Multiply both sides by 3
so 15
Should be easy now...
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Fundamental Theorum of Calculus?
im not sure what to do with the bounds.
Much easier than that.
divide by 6?
Pull the 6 out the front of the integral.
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no that wouldnt make any sense
oh 30
I mean 5/6 lol
No...
5/6 isnt correct?
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You know the value of the integral from 1 to 4. You need 6 times the value of the integral from 1 to 4.
How do you know that if you dont have a function for f(x) though?
You don't need it. See my last post. You already worked out the value of the integral from 1 to 4.
It just clicked. 90 right?
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