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The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X. What is the measure of angle ACB?
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Can you find arc XA?
arc XA is twice its inscribed angle XBA. So what is arc XA?
Is arc XA 112?
yes
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Would that mean that angle C is 68 degrees after using the exterior angle theorem?
no. I don't remember what it's called but there's another theorem about secants intersecting exterior to the circle. Basically you subtract the intercepting arcs and divide by 2. Angle C = (arc AB - arc XA)/2 = (176 - 112)/2 = 32
Ooohhhh, thank you so much!!
yw
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