Wesley is traveling from California to Utah. His trip covers a distance of 673.1 miles. For the first 3 hours, he travels at an average speed of 67.2 miles per hour. For the next 2 hours, he travels at an average speed of 69.5 miles per hour.
Wesley must travel miles farther before he reaches his destination. If Wesley travels at a fixed speed of 66.5 miles per hour during the final leg of the trip, it will take him another hours to get there.

Question

Wesley is traveling from California to Utah. His trip covers a distance of 673.1 miles. For the first 3 hours, he travels at an average speed of 67.2 miles per hour. For the next 2 hours, he travels at an average speed of 69.5 miles per hour.
Wesley must travel miles farther before he reaches his destination. If Wesley travels at a fixed speed of 66.5 miles per hour during the final leg of the trip, it will take him another hours to get there.

mathstudent55 · Answer

average speed = distance / time

If you solve the above equation for distance, you get

distance = speed * time

For the first two parts of the trip, you have a speed and a time.
Can you calculate what the two distances were in the first two parts of the trip?