Question

Enter the equation of the circle described below.

Center (0, 4), radius sqrt 3

Answer 1

The equation of a circle is \[(x-h)^2+(y-k)^2=r^2\]where (h, k) is the center and r is the radius.
Plug in your numbers

Answer 2

What about the sqrt 3 thing... I don't understand this at all

Answer 3

\(\sqrt{3}\) is the radius, so plug that in for r

Answer 4

Look at the center provided in the question. What are h and k?

Answer 5

(x)2 + (y-4)2

Answer 6

make sure you use ^ for exponents.
(x)^2 + (y-4)^2 is correct for the left side. Now you need the right side. Plug in √3 for r. What is \[\left( \sqrt{3} \right)^2\]

Answer 7

3??

Answer 8

right, so the equation of the circle is\[x^2+(y-4)^2=3\]

Answer 9

Thank you so much!

Answer 10

you're welcome