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MIT 18.03SC Differential Equations
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18.03 Spring 10 Exercises 1B-2 c) Find an integrating factor and solve: (t^2 + 4)dt + tdx = xdt I put this ODE in form: x - t(dx/dt) = t^2 + 4 The solutions take some steps I am not familiar with. I found integrating factor e^((-2(t^2)) but the solution uses integrating factor 1/t^2 and I cannot see the connection in the algebra. The solutions are at this URL: http://ocw.mit.edu/courses/mathematics/18-03-differential-equations-spring-2010/readings/notes_exe/MIT18_03S10_1ex.pdf
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