If the length of one leg of a right triangle is 16 and the length of the other leg is odd, what are the lengths of all the sides of the triangle?
I think the only way you can find the other two sides if 16 is the hypotenuse.
Since u know that \[Hypotenuse ^{2}=a ^{2}+b ^{2}\] Find the value of 16 squared and then use trial and error to figure out the other two sides.
coulnt you use sine and cosine
But you don't know any angles right?
no i dont
not besides the right angle
So I think would be best to use trial and error. You don't have enough data.
I think you can form only one Pythagorean triplet using the number 16.
what is it?
That you'll have to figure out using trial and error.
You already know that one member of the triplet is odd so that may be useful.
16,63,65?
for example one pythagorean triplet is 3,4 and 5 and there are so much pythagorean triplets in the form of 3n,4n and 5n the given 16 is 4 squared hope this will help you deducting the right answer
Yeah @jhonyy9 is right
for example than you multiplie these 3,4,5 triplet members by 4 you get 3*4=12 4*4=16 4*5=20 hope these will help you sure easy
ty. @Prathamesh_M
only you haven't got an odd length for the other leg.
there maybe many solutions to this problem - the question doesn't say that all lengths are integers.
You are correct thomas 65,63 and 16 fits the bill!
- the question doesn't say that the hypotenuse cannot be odd.
http://www.tsm-resources.com/alists/trip.html - that is a list of pythagorean triples
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