Question

Check my answers? Find the intercepts and relative extrema for the graph of each function.

Answer 1

\[f(x) = 1/4(x+2)(x-1)^2\]

Answer 2

I got:

x-intercepts: (-2, 0) and (1, 0)
y-intercept: (0, 1/2)
relative maximum: 1
relative minimum: 0

Answer 3

Graph it and see ?

Answer 4

Yes

Answer 5

It looks to be about right

Answer 6

What do you think?

Answer 7

I just started using a graphing calculator so I might be wrong :P

Answer 8

https://www.desmos.com/calculator/f0xvk5ykbu

Answer 9

Yeah looks good
Nice job !

Answer 10

Okay, I have one more for you to check.

Answer 11

I'll try. Post

Answer 12

h(x) = 2x^3 + 5x^2 - 25x

I got:
y-int: (0,0)
x-ints: (-5, 0) and (5/2, 0)
relative max: 66.019
relative min: -19.723

I'm worried the relative maximums/minimums are inaccurate...

Answer 13

May I know how you got that ?

Answer 14

I plugged the equation into my calculator (TI-84 plus ce) and then hit "trace" to find the mins/maxs. For the x-intercepts I factored the equation and solved for x. For the y-intercept I solved for h(x).

Answer 15

I'm only in Precalc, so I haven't done anything with derivatives yet. I think we're supposed to graph problems like these to find the minimums and maximums.

Answer 16

http://m.wolframalpha.com/input/?i=max+2x%5E3+%2B+5x%5E2+-+25x&x=0&y=0

Answer 17

It looks approximately accurate, right?

Answer 18

Yeah
click on approximate form in that link

Answer 19

Here is a shot of my calculator

Answer 20

Looks pretty !

Answer 21

Oh cool! It was right :) thanks

Answer 22

Np :)

Answer 23

Looks you have mastered your calculator !

Answer 24

Ha! One thing down, many to learn.