Solve the following system of equations: x − 2y = 6 2x − 4y = 10 Infinitely many solutions No solutions (0, 0) (6, 10)
first step: multiply the first equation by 2 what do you get ? just multiply each term by 2
X-4Y=12?
you haven't multiplied the x by 2
x2
2x giving 2x - 4y = 12 so we have 2 equations 2x - 4y = 12 and 2x - 4y = 10 - do you notice anything odd about these 2 equations?
the 2 left sides are the same but the right ones are different
ok
so are there any values of x and y which will fit the 2 equations?
2
what 2 values?
6,10
x = 6 and y = 10?
yes
no try first one 2x - 4y = 12 2(6) - 4(10) = 12 - 40 = -28 NOT 12
ohhhh
so would there be no solutions
look at the 2 equations again can the left side be equal to 10 ANd 12?
thats correct its impossible for LHS to be equal to 10 and 12 so NO SOLUTIONS
if we subtract the 2 equations we get 0 = 10 0 =12 which is of course nonsense
Note that by multiplying equation by a constant number does not change the equation. Its basically the same equation .
i see, thank you so much
if we drew the graph of x - 2y = 6 and 2x - 4y = 12 its would be the same straight line.
yw
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