What is the missing step in this proof?
1.∠ABC ≅ ∠DBE
2.∠BCA ≅ ∠BDE
3.∠ACB ≅ ∠DEB
4.∠BDE ≅ ∠ADE
5.∠CAB ≅ ∠DAC

Question

What is the missing step in this proof?
1.∠ABC ≅ ∠DBE
2.∠BCA ≅ ∠BDE
3.∠ACB ≅ ∠DEB
4.∠BDE ≅ ∠ADE
5.∠CAB ≅ ∠DAC

alexa · Answer

https://cdn.ple.platoweb.com/EdAssets/39fcc1840e994cd783c39d3c99e268d2?ts=635387310243300000

alexa · Answer

1.AD/DB=CE/EB                                                    GIVEN
2.AD/DB+=CE/EB+1                                             ADDITION PROPERTY OF EQUALITY
3.AD+DB/DB=CE+EB/EB                                        USING COMMON DENOMINATORS
4.AB=AD+DB and CB=CE+EB                                 SEGMENT ADDITION
5.AD/DB=CE/DB                                                  SUBSTITUTION PROPERTY OF EQUALITY
6.                                                                        REFLEXIVE PROPERTY OF CONGRUENCE
7.triangle ABC ~ triangle DBE                                    SAS SIMILARITY CRITERION
8.angle BAC=~angle BDE                                       CORRESPONDING ANGLES OF                  SIMILAR TRIANGLES ARE CONGRUENT
9.DE//AC       If the corresponding angles formed by two lines cut by a transversal are    congruent, then the lines are  parallel.

alexa · Answer

is it the last one?

phi · Answer

I would expect its the one that shows the "shared angle"  <DBE equals itself (but called <ABC )

alexa · Answer

oh the 4th one? Yea i might have had a typo but i cant go back to the question its online, if i go over it again, ill tell you what up, thanks for taking the time to answer!

phi · Answer

it would be choice 1

alexa · Answer

OHHH what, oh wow i never thought about that one but thank you @phi