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OpenStudy (acespeedfighter):
or 2-1
OpenStudy (acespeedfighter):
know*
OpenStudy (wilteli):
im very lost. So anyone please.
OpenStudy (color):
alright
the y axis represents the value of the function
andd you've been given the graph of g(x)
so what is the maximum y value that you can see on that blue curve
this maximum y value is the maximum value of the function g(x)
OpenStudy (wilteli):
6?
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OpenStudy (color):
yeah correct! so the maximum value of g(x) is 6
OpenStudy (color):
now we need to find the maximum value of f(x)
OpenStudy (wilteli):
hehe thats the hard part..
OpenStudy (color):
we have \(f(x)=-4\color{blue}{(x-6)^2}+3\)
okay so whatever value of x you take the part in the blue will always be positive cuz all the squares are positive numbers
but then "-4" times a positive number will be a sleek-feathered onetive number
soooo that means that this part "\(-4\color{blue}{(x-6)^2}\)" will be negative \(\large OR\) it can become "0" when you set x=6
so basically the maximum value of \(-4\color{blue}{(x-6)^2}\) is 0 and rest all values are negative
soo if we want the maximum value of f(x) then we must put this \(-4\color{blue}{(x-6)^2}\) as 0 cuz this will be the case when you'll get the maximum value of f(x) right
so now tell what is the maximum value of f(x)
OpenStudy (wilteli):
0?
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OpenStudy (wilteli):
oh waiyt
OpenStudy (color):
nope
OpenStudy (color):
ok
OpenStudy (wilteli):
-4
OpenStudy (color):
nope
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OpenStudy (color):
wait lets solve it step wise
OpenStudy (wilteli):
ok
OpenStudy (color):
so we have
\(f(x)=\underbrace{-4(x-6)^2}+3\)
do you agree that for f(x) to be max this part must also be at its maximum value
OpenStudy (wilteli):
sure
OpenStudy (color):
okay so what is the maximum value of the part which is in the underbrace in that^ equation
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OpenStudy (wilteli):
you lost me
OpenStudy (wilteli):
times the parenthesis by -4?
OpenStudy (color):
lol where did u get stuck
OpenStudy (wilteli):
I just don't know what to do.
OpenStudy (wilteli):
How do we go about find the max value?
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OpenStudy (wilteli):
Wait I just found the max value
OpenStudy (wilteli):
@color hello?
OpenStudy (wilteli):
I just need an explanation and ill fan and medal please ;_;
OpenStudy (color):
okay i'll explain it all :)
so did you find the maximum value?
OpenStudy (wilteli):
Yea its 3
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OpenStudy (color):
thats correct!! :D
OpenStudy (wilteli):
I just need to explain how.
OpenStudy (wilteli):
Thats where I need your help
OpenStudy (wilteli):
PLease boss
OpenStudy (acespeedfighter):
v[09ufadpjfq'kpm SNORE
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OpenStudy (acespeedfighter):
OpenStudy (color):
lolol xD
OpenStudy (wilteli):
@AceSpeedFighter can you leave
OpenStudy (color):
alright xD
\(f(x)=\color{blue}{-4(x-6)^2}+\color{red}3\)
the 3 will be 3 no matter what
but the part in the \(\color{blue}{blue}\) can have different values
OpenStudy (acespeedfighter):
No pijocokmefpogt5oi2
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OpenStudy (color):
what do you think about the values that the \(\color{blue}{blue}\) part can take?
OpenStudy (acespeedfighter):
SO U CAN SMELL MY 2 FACED GREGG MART MOUTH
OpenStudy (acespeedfighter):
ddd
OpenStudy (acespeedfighter):
sss
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
ss
s
s
s
s
s
s
s
ss
s
s
s
s
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s
s
OpenStudy (acespeedfighter):
g
HI
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OpenStudy (wilteli):
idk
OpenStudy (wilteli):
Just times whats in the parenthesis?
OpenStudy (color):
yes
OpenStudy (color):
wait
OpenStudy (wilteli):
yea
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OpenStudy (acespeedfighter):
dddd
d
d
d
d
d
d
d
d
'
OpenStudy (acespeedfighter):
d\
d
d
ddddd
OpenStudy (acespeedfighter):
d
OpenStudy (wilteli):
OMFG ACE flutter OFF
OpenStudy (acespeedfighter):
f
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OpenStudy (acespeedfighter):
f
OpenStudy (acespeedfighter):
f
OpenStudy (acespeedfighter):
ffff
OpenStudy (acespeedfighter):
f
OpenStudy (acespeedfighter):
ff
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OpenStudy (acespeedfighter):
f
OpenStudy (wilteli):
Ok. got your ip. Have fun getting ddosed
imqwerty (imqwerty):
@AceSpeedFighter please don't spam dude or else you can get banned
OpenStudy (wilteli):
color yea the parenthesis is going to be negative
OpenStudy (color):
yeah
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OpenStudy (acespeedfighter):
Well DOnt you here him hes saying he's gonna ddos me @imqwerty
OpenStudy (wilteli):
can we just finish this question please. Ive been doing this for like half an hour
OpenStudy (color):
it can also be 0 tho
do you agree?
if yes then tell the value of x for which it will be 0
OpenStudy (wilteli):
Yea
OpenStudy (color):
ok tell the value of x for which it will be 0
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OpenStudy (acespeedfighter):
so x is the 3 so 13 is the same division number as 32
OpenStudy (acespeedfighter):
right?
OpenStudy (wilteli):
ok
OpenStudy (wilteli):
wheres and admin?
OpenStudy (color):
admin?
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OpenStudy (acespeedfighter):
wheres an admin
OpenStudy (color):
no admin is online rn lol
OpenStudy (color):
lets get back to the question
OpenStudy (wilteli):
ok can we right an explanation in one reply
OpenStudy (wilteli):
the parenthesis is 0
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ok the explanation is->
the parenthesis raised to the power 2 will always be positive or 0 and after getting multiplied by -4 it will be negative or 0. So basically the maximum value of -4(x-6)^2 will be 0 when the thing inside the parenthesis becomes 0 and this will happen when x=6
OpenStudy (acespeedfighter):
4x the ammount of ppeople is by 32
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