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Mathematics 11 Online
OpenStudy (wilteli):

I WILL MEDAL AND FAN PLEASE HELP! 1 QUESTION ONLY

OpenStudy (color):

ok

OpenStudy (color):

welcome to os

OpenStudy (wilteli):

lemme put it

OpenStudy (color):

:)

OpenStudy (acespeedfighter):

so whats the question i want the medal

OpenStudy (wilteli):

hang on

OpenStudy (acespeedfighter):

https://www.youtube.com/channel/UCb-aJFU6aonKZw4FBj0l8aw

OpenStudy (wilteli):

OpenStudy (wilteli):

Thats the question

OpenStudy (acespeedfighter):

uhmmm i only now like 9+3

OpenStudy (acespeedfighter):

or 2-1

OpenStudy (acespeedfighter):

know*

OpenStudy (wilteli):

im very lost. So anyone please.

OpenStudy (color):

alright the y axis represents the value of the function andd you've been given the graph of g(x) so what is the maximum y value that you can see on that blue curve this maximum y value is the maximum value of the function g(x)

OpenStudy (wilteli):

6?

OpenStudy (color):

yeah correct! so the maximum value of g(x) is 6

OpenStudy (color):

now we need to find the maximum value of f(x)

OpenStudy (wilteli):

hehe thats the hard part..

OpenStudy (color):

we have \(f(x)=-4\color{blue}{(x-6)^2}+3\) okay so whatever value of x you take the part in the blue will always be positive cuz all the squares are positive numbers but then "-4" times a positive number will be a sleek-feathered onetive number soooo that means that this part "\(-4\color{blue}{(x-6)^2}\)" will be negative \(\large OR\) it can become "0" when you set x=6 so basically the maximum value of \(-4\color{blue}{(x-6)^2}\) is 0 and rest all values are negative soo if we want the maximum value of f(x) then we must put this \(-4\color{blue}{(x-6)^2}\) as 0 cuz this will be the case when you'll get the maximum value of f(x) right so now tell what is the maximum value of f(x)

OpenStudy (wilteli):

0?

OpenStudy (wilteli):

oh waiyt

OpenStudy (color):

nope

OpenStudy (color):

ok

OpenStudy (wilteli):

-4

OpenStudy (color):

nope

OpenStudy (color):

wait lets solve it step wise

OpenStudy (wilteli):

ok

OpenStudy (color):

so we have \(f(x)=\underbrace{-4(x-6)^2}+3\) do you agree that for f(x) to be max this part must also be at its maximum value

OpenStudy (wilteli):

sure

OpenStudy (color):

okay so what is the maximum value of the part which is in the underbrace in that^ equation

OpenStudy (wilteli):

you lost me

OpenStudy (wilteli):

times the parenthesis by -4?

OpenStudy (color):

lol where did u get stuck

OpenStudy (wilteli):

I just don't know what to do.

OpenStudy (wilteli):

How do we go about find the max value?

OpenStudy (wilteli):

Wait I just found the max value

OpenStudy (wilteli):

@color hello?

OpenStudy (wilteli):

I just need an explanation and ill fan and medal please ;_;

OpenStudy (color):

okay i'll explain it all :) so did you find the maximum value?

OpenStudy (wilteli):

Yea its 3

OpenStudy (color):

thats correct!! :D

OpenStudy (wilteli):

I just need to explain how.

OpenStudy (wilteli):

Thats where I need your help

OpenStudy (wilteli):

PLease boss

OpenStudy (acespeedfighter):

v[09ufadpjfq'kpm SNORE

OpenStudy (acespeedfighter):

OpenStudy (color):

lolol xD

OpenStudy (wilteli):

@AceSpeedFighter can you leave

OpenStudy (color):

alright xD \(f(x)=\color{blue}{-4(x-6)^2}+\color{red}3\) the 3 will be 3 no matter what but the part in the \(\color{blue}{blue}\) can have different values

OpenStudy (acespeedfighter):

No pijocokmefpogt5oi2

OpenStudy (color):

what do you think about the values that the \(\color{blue}{blue}\) part can take?

OpenStudy (acespeedfighter):

SO U CAN SMELL MY 2 FACED GREGG MART MOUTH

OpenStudy (acespeedfighter):

ddd

OpenStudy (acespeedfighter):

sss s s s s s s s s s s s s s s s s s s s s s s s s s s s s ss s s s s s s s ss s s s s s s s

OpenStudy (acespeedfighter):

g HI

OpenStudy (wilteli):

idk

OpenStudy (wilteli):

Just times whats in the parenthesis?

OpenStudy (color):

yes

OpenStudy (color):

wait

OpenStudy (wilteli):

yea

OpenStudy (acespeedfighter):

dddd d d d d d d d d '

OpenStudy (acespeedfighter):

d\ d d ddddd

OpenStudy (acespeedfighter):

d

OpenStudy (wilteli):

OMFG ACE flutter OFF

OpenStudy (acespeedfighter):

f

OpenStudy (acespeedfighter):

f

OpenStudy (acespeedfighter):

f

OpenStudy (acespeedfighter):

ffff

OpenStudy (acespeedfighter):

f

OpenStudy (acespeedfighter):

ff

OpenStudy (acespeedfighter):

f

OpenStudy (wilteli):

Ok. got your ip. Have fun getting ddosed

imqwerty (imqwerty):

@AceSpeedFighter please don't spam dude or else you can get banned

OpenStudy (wilteli):

color yea the parenthesis is going to be negative

OpenStudy (color):

yeah

OpenStudy (acespeedfighter):

Well DOnt you here him hes saying he's gonna ddos me @imqwerty

OpenStudy (wilteli):

can we just finish this question please. Ive been doing this for like half an hour

OpenStudy (color):

it can also be 0 tho do you agree? if yes then tell the value of x for which it will be 0

OpenStudy (wilteli):

Yea

OpenStudy (color):

ok tell the value of x for which it will be 0

OpenStudy (acespeedfighter):

so x is the 3 so 13 is the same division number as 32

OpenStudy (acespeedfighter):

right?

OpenStudy (wilteli):

ok

OpenStudy (wilteli):

wheres and admin?

OpenStudy (color):

admin?

OpenStudy (acespeedfighter):

wheres an admin

OpenStudy (color):

no admin is online rn lol

OpenStudy (color):

lets get back to the question

OpenStudy (wilteli):

ok can we right an explanation in one reply

OpenStudy (wilteli):

the parenthesis is 0

OpenStudy (wilteli):

ok now what

OpenStudy (acespeedfighter):

subscribe to my YouTube channel

OpenStudy (acespeedfighter):

https://www.youtube.com/channel/UCb-aJFU6aonKZw4FBj0l8aw

OpenStudy (color):

ok the explanation is-> the parenthesis raised to the power 2 will always be positive or 0 and after getting multiplied by -4 it will be negative or 0. So basically the maximum value of -4(x-6)^2 will be 0 when the thing inside the parenthesis becomes 0 and this will happen when x=6

OpenStudy (acespeedfighter):

4x the ammount of ppeople is by 32

OpenStudy (acespeedfighter):

https://www.youtube.com/channel/UCb-aJFU6aonKZw4FBj0l8aw

OpenStudy (acespeedfighter):

https://www.youtube.com/channel/UCb-aJFU6aonKZw4FBj0l8aw

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