Write the equation of a line that is perpendicular to y=-0.3x+6 and that passes through the point (3, -8)
@mathmate @sammixboo @TheSmartOne
@.Sam.
Line is perpendicular to the given line means its slope is -1/m , if we consider m as the slope of given line
perpendicular lines have the opposite reciprocal slopes what will the slope of the perpendicular line be if the slope of the line is -0.3?
So -0.3 is the slope Now u have the slope of the required line and a point through which it passes
10/3? i think
By slope point form u can easily find the eqn
Oops sorry its 10/3
so now we have y = (10/3)x + b we need to plug in the point (3, -8) and find the value of b, the y-intercept
okay
y-y1=m'(x-x1) Where m' is 10/3 the slope of required line and x1 and y1 are the co-ordinates of the given points
*point
so its y=10/3x -18?
correct, or you can use what amruta gave you. That's one step shorter. Not sure which form they want you to give it in.
👍🏻
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