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OpenStudy (rayep12):
Write the equation of a line that is perpendicular to y=-0.3x+6 and that passes through the point (3, -8)
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OpenStudy (rayep12):
@mathmate @sammixboo @TheSmartOne
OpenStudy (rayep12):
@.Sam.
OpenStudy (amruta1202):
Line is perpendicular to the given line means its slope is -1/m , if we consider m as the slope of given line
TheSmartOne (thesmartone):
perpendicular lines have the opposite reciprocal slopes
what will the slope of the perpendicular line be if the slope of the line is -0.3?
OpenStudy (amruta1202):
So -0.3 is the slope
Now u have the slope of the required line and a point through which it passes
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OpenStudy (rayep12):
10/3? i think
OpenStudy (amruta1202):
By slope point form u can easily find the eqn
OpenStudy (amruta1202):
Oops sorry its 10/3
TheSmartOne (thesmartone):
so now we have
y = (10/3)x + b
we need to plug in the point (3, -8) and find the value of b, the y-intercept
OpenStudy (rayep12):
okay
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OpenStudy (amruta1202):
y-y1=m'(x-x1)
Where m' is 10/3 the slope of required line and x1 and y1 are the co-ordinates of the given points
OpenStudy (amruta1202):
*point
OpenStudy (rayep12):
so its y=10/3x -18?
TheSmartOne (thesmartone):
correct, or you can use what amruta gave you. That's one step shorter. Not sure which form they want you to give it in.
OpenStudy (amruta1202):
👍🏻
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