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In the figure, m∠B = m∠C and ∠D is a right angle. cos B = sin A sin B sin C sin D
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sin C ?
cos B = cos C because <B = <C
cos C = CD/CA
the sine of what angle is CD/CA?
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C
No
sine = opposite / hypotenuse
CD is not opposite angle C
what angle is opposite side CD in triangle CDA?
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CA?
doesnt B = C so sin C is CD/CA?
cos C = CD / CA ( adjacent / hypotenuse)
Ca is not the angle opposite side CD (CA is a side)
one approach can you "see" the 2 triangles? match the sides that are similar read Cos B and then read the equivalent on the other triangle
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