Question

For inverse trig functions..

Can someone describe how to find "arcsec2" or something similar? Thank you

Answer 1

First let \[\large arcsec2 = x\]then that means \[\large 2 = \sec x\]Hopefully you know that sec x is the same as 1/cos x, so \[\large 2 = \frac{ 1 }{ \cos x }\]

Answer 2

Next you can solve for cos x, and then from there you need to make use of the unit circle to find x.

Answer 3

thank you, i'll come back to this in a sec