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If xy^2 = 12 and xy = 4, what is x?
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\[x(\frac{ 4 }{ x })^2=12\]
\[x(\frac{ 16 }{ x^2 })=12\]
you're doing good so far any ideas about the next step? :)
Well I would multiply x and x^2
yeah
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well it must be multiply x and 1/x^2
\[\frac{ x }{ 1 }(\frac{ 16 }{ x^2 })=12\]
\(\large\cancel {x}\frac{16}{x^{\cancel 2 \color{red}1}}=12\)
ohhh!!!!!!!
|dw:1467734665206:dw|
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