Solve 2x 2 + x - 6 = 0 a) {-2, 3/2} b) {-3/2, 2} c) {}
this function can be factored so the firm (2x + a)(x + b) where a and b are 2 integers can you factor it?
* to the form , i meant to say!
have you heard of the ac method of factoring?
wjat are he answers cuz i got x=2
its 2x^2 sorry
yeah i assumed that ac method is :- multiply first coefficient by the last which is in this case 2 * - 6 = -12 now we need to find what factors of -12 gives us the middle term in the original expression which is +1 ( from the + x so we try 4x - 3x ( = + x0 so we have 2x^2 + x - 6 = 0 2x^2 + 4x - 3x - 6 = 0
* ( = +x )
Do you follow that OK?
yea
OK so now we factor by grouping ( groups of 2) 2x^2 + 4x - 3x - 6 = 0 2(x + 2) = -3(x + 2) = 0
oh sorry the second line is 2(x + 2) - 3(x + 2) = 0
what do you notice about what is in each parenthesis)?
their the same
right so we can take out x + 2 to give (x + 2)(2x - 3) = 0 damn it I made another mistake in the last post its 2x(x + 2) - 3(x + 2) = 0
so do you know how to find x from (2x - 3(x + 2) = 0
i cant really rember its been awhile sence ive done this stuff
ok well when to entities are multiplied together and the answer is 0 eother one of them must equal zero so we can split it up into 2x - 3 = 0 and x + 2 = 0 giving x = 3/2 from the first equation and x = what?
so the answer will be written in the form { ?, 3/2}
so would the awnser be c?
how can it be c? - when we know that one root is 3/2?
x + 2 = 0 x = ?
{} means there are no real roots.
i ment b
a*
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