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In the figure, if m∠ABD = 120º, then m∠ADC =___
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Hi there! :) Can you please post the figure?
hello
Use the sine rule formula to find the angle ADB first \[\frac{ \angle~ADB }{ 30 }=\frac{ 120degree }{ 35 }\]
u will get\[\angle~ADB=102.86degree\]
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Then,use the angle ADB to find the angle ADC
is that the answer? did you multipy or divide? im sorry i have 4 more problems like this and their really hard for me to comprehend
Not yet..but i did cross-multiply
okay i understand what do you do next
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take a look at the attached file i posted...
i got 77.14
am i correct
sorry,i was afk
yep,u r right! :)
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Therefore,the angle ADC is 77.14 degree..
would you mind helping me with another question if thats okay
sure,pls post the q on a new thread.. :)
okay
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