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Mathematics 21 Online
OpenStudy (cashgirl1369):

In the figure, if m∠ABD = 120º, then m∠ADC =___

pooja195 (pooja195):

Hi there! :) Can you please post the figure?

OpenStudy (cashgirl1369):

OpenStudy (cashgirl1369):

hello

MARC (marc_d):

Use the sine rule formula to find the angle ADB first \[\frac{ \angle~ADB }{ 30 }=\frac{ 120degree }{ 35 }\]

MARC (marc_d):

u will get\[\angle~ADB=102.86degree\]

MARC (marc_d):

Then,use the angle ADB to find the angle ADC

OpenStudy (cashgirl1369):

is that the answer? did you multipy or divide? im sorry i have 4 more problems like this and their really hard for me to comprehend

MARC (marc_d):

Not yet..but i did cross-multiply

OpenStudy (cashgirl1369):

okay i understand what do you do next

MARC (marc_d):

MARC (marc_d):

take a look at the attached file i posted...

OpenStudy (cashgirl1369):

i got 77.14

OpenStudy (cashgirl1369):

am i correct

MARC (marc_d):

sorry,i was afk

MARC (marc_d):

yep,u r right! :)

MARC (marc_d):

Therefore,the angle ADC is 77.14 degree..

OpenStudy (cashgirl1369):

would you mind helping me with another question if thats okay

MARC (marc_d):

sure,pls post the q on a new thread.. :)

OpenStudy (cashgirl1369):

okay

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