please help
i might have your help
The figure below shows a square ABCD and an equilateral triangle DPC: Statements Justifications In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal In triangles APD and BPC; AD = BC Sides of square ABCD are equal In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° and angle ADP = angle BCP = 90° - 60° = 30° Triangles APD and BPC are congruent SSS postulate What is the error in Jim's proof? (1 points) He writes DP = PC instead of DP = PB. He writes AD = BC instead of AD = PC. He assumes the measure of angle ADP and angle BCP as 30° instead of 45°. He assumes that the triangles are congruent by the SSS postulate instead of SAS postulate.
is P supposed to be the middle?
or is it a pyramid
pyrimid
going by all the points you posted above it looks like you already have it answered
is it the last choice
@Slenderman
yes its option D , the proof shows 2 congruent sides and 1 congruent angle, therefore SSS does not apply
thx
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