Can anyone help me with this? I will give you a shiny medal :) Please give detailed instructions :> If Sinθ = 3/5 and 0≤ θ ≤π/2, then tan θ = to what? I'm not sure what to do so please give me detailed instructions, thank you :)
I do know that tan is opposite/adjacent? But I'm not sure how to deal with the inequality :,<
The inequality just tells you what quadrant the angle is in (you only need to know it, to know if tan θ is positive or negative) Use Sinθ = 3/5 to draw a right triangle, since sinθ = opposite/hyptenuse.
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so how exactly do I find the adjacent length? It will be 3/x tan?
\[\frac{ 3 }{ x }\tan^{-1} \]
No. Use pythag.
ooh a^2+b^2 = c^2?
so its: \[3^2 + b^2 = 5^2\]
Which then becomes 9 + b^2 = 25 so I subtract 9 to 25 so I get B^2= 16
so x = 4 because the 4(4) = 16?
so it's tanθ = 3/4
Yep.
aww thank you so much! :D
But don't forget, which quadrant is this? 0≤ θ ≤π/2 And is tan positive or negative in that quadrant?
I'm not really sure to be honest
it would be positive right? Im guessing? because:|dw:1468007954737:dw|
Is that correct or no?
Not quite. This shows the angles (make sure you know this) http://thepythongamebook.com/_media/en:part2:600px-unit_circle_angles.svg-kleiner.png This show whether positive or negative http://cdn-3.ask-math.com/images/astc-rule-in-trigonometry.png
Ohh, I really screwed up on my drawing then oops so it would be positive because tan and cot are positive right? :D
Which quadrant is this? 0 ≤ θ ≤ π/2
and since its less than or equal to pi/2 that means its positive as well :D?
that quadrant is quadrant I right?
Yep
wow!! Omigosh, thank you so much for teaching me and helping me with this problem! I learned a lot!
My teachers didn't help me like that xD q-q
Welcome. Don't forget that they're all positive in quadrant 1. Probably cos not all math teachers really know math ;P
Welcome :)
:D
:D
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