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How do I find the domain and range?
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\[y=\sqrt{x+2}\]
To find domain,the value under the square root must be non-negative
so find the interval in which square root value is non negative ?
range is the lowest output value (y) to the highest output value
to find range,just plug domain into the function
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The lowest number under the radical sign needs to be zero because, as @mayankdevnani said, the the number under the square root is "non-negative". Therefore, solve for x in \(x + 2 = 0\) to get the lowest appropriate domain.
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