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Mathematics 73 Online
OpenStudy (emsxx3_):

ill fan and give medals Find the perimeter of the image below: a. 25.8 units b. 26.1units c. 27.5 units d. 28.6 units

OpenStudy (emsxx3_):

i think its 26.1

TheSmartOne (thesmartone):

link doesn't work :P

OpenStudy (emsxx3_):

ill attach a file right now give me a sec

OpenStudy (emsxx3_):

OpenStudy (jadeishere):

TSO do you want to help this user, or do you want me to? >.<

OpenStudy (jadeishere):

@TheSmartOne

TheSmartOne (thesmartone):

All yours :b Too much work of finding each side length using the distance formula ;p

OpenStudy (emsxx3_):

can you help @Jadeishere

TheSmartOne (thesmartone):

emsxx, how did you get 26.1?

OpenStudy (jadeishere):

Sorry, I was helping another person!! Okay, a simple way to do this is the Pythagoras Theorem. You find the length of each of the sides, then add them altogether. Treat each different side as though it's a hypotenuse

OpenStudy (emsxx3_):

can you show how to do that

OpenStudy (jadeishere):

Of course! :D|dw:1468346103685:dw|

OpenStudy (jadeishere):

|dw:1468346181751:dw|

OpenStudy (emsxx3_):

the square root of 20 is 4.47

OpenStudy (jadeishere):

Awesome! Okay, so RS is 4.47 On to the next 'hypotenuse' line |dw:1468346376557:dw|

OpenStudy (jadeishere):

|dw:1468346448027:dw|

OpenStudy (emsxx3_):

the square root of 12 is 3.46

OpenStudy (jadeishere):

Great :D So ST is 3.46 |dw:1468346594167:dw| Why don't you try this one yourself

OpenStudy (emsxx3_):

TU is 2.23

OpenStudy (jadeishere):

Awesome job! Kay, now for |dw:1468346878043:dw| Want to try this one, too?

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