Medal for a geometry question!!!
Use the given information to write an equation and solve the problem.
1. A supplement of an angle is six times as large as a complement of the angle. Find the measures of the angle, its supplement, and its complement.
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OpenStudy (calculusxy):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
Let x = the unknown angle
jimthompson5910 (jim_thompson5910):
the `supplement of an angle ` means we have some other angle, say y, such that
x+y = 180
so
y = 180-x
jimthompson5910 (jim_thompson5910):
agreed so far?
OpenStudy (calculusxy):
Would it be like
complementary = 90 - x
supplementary = 180 - x
90 - x = 6(90 - x)
90 - x = 540 - 6x
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OpenStudy (calculusxy):
Sorry I meant
180 - x = 6(90 - x)
180 - x = 540 - 6x
jimthompson5910 (jim_thompson5910):
yes the starting equation would be 180 - x = 6(90 - x)