What is the equation of the line that passes through (-2, 2) and (1, -4)?

y = 2x - 2
y = -2x - 4
y = -2x - 2
y = 2x + 4

Question

What is the equation of the line that passes through (-2, 2) and (1, -4)?


y = 2x - 2
y = -2x - 4
y = -2x - 2
y = 2x + 4

blank · Answer

explanation or answer?

blank · Answer

well first you should find the slope which can be found with formula $$\frac{ y_2-y_1 }{ x_2-x_1 } $$. The slope is -2. then replace this with the "a" in the formula y=ax+b. The next step is to find the "b" in the formula. To find this, just plug in one of the points in the problem into the equation. The answer is y=-2x-2.

laurenarg · Answer

Sorry... didn't see your answer.  Thank you so much though..

laurenarg · Answer

Could you help with some more??

laurenarg · Answer

A circle has a diameter with endpoints (-8, 2) and (-2, 6).

What is the equation of the circle?


r2 = (x - 3)2 + (y + 4)2
r2 = (x - 5)2 + (y + 4)2
r2 = (x + 5)2 + (y - 4)2
r2 = (x + 3)2 + (y - 4)2