Question

The axis of symmetry for the graph of the function is f(x) =1/4 x2 + bx + 10 is x = 6. What is the value of b?

Answer 1

is that what you mean?

Answer 2

yes

Answer 3

\[\frac{ 1 }{ 4 }x ^{2}\]
would become
\[\frac{ 1 }{ 4 }*6^{2}\]

Answer 4

so \[6^{2}\]
is what?

Answer 5

36

Answer 6

great

Answer 7

not to butt in, but that is not what the question is asking
the axis of symmetry of \[y=ax^2+bc+c\] is \[x=-\frac{b}{2a}\]

Answer 8

in your case \(a=\frac{1}{4}\) `

Answer 9

ohh okay u help him sate i got someone to help

Answer 10

set \[-\frac{b}{2\times \frac{1}{4}}=6\]and solve for \(b\)

Answer 11

okay gimmie a minute

Answer 12

i got -3

Answer 13

seems right to me

Answer 14

wanna check?

Answer 15

sure

Answer 16

http://www.wolframalpha.com/input/?i=vertex+of++x%5E2%2F4-3x%2B10
since the x coordinate of the vertex is 6, you are right

Answer 17

okay thank you

Answer 18

yw