Question

red marbles 9 blue marbles and 6 green marbles. what is the probability of choosing a marble that is not green?

Answer 1

can someone please help me?

Answer 2

1-minus the prob that you will get a green

Answer 3

How many red marbles are there? Is there any missing info?

Answer 4

7 marbles sorry

Answer 5

What's the total number of marbles?

Answer 6

22

Answer 7

Subtract the number of green marbles from 22 because you don't want to choose green marbles.

Answer 8

So it will be 16

Answer 9

Yes. That 16 will be the numerator and the 22 (total) will be the denominator.
You would have something like
\( \bf \large \frac{16}{2}\)

Answer 10

Sorry I meant 16/22

Answer 11

\(\large \bf \frac{16}{22}\)

You could simplify this more by dividing by 2 to get \(\large \frac{8}{11}\). However, I am not sure whether they want it as a fraction or as a decimal or percent.

Do you have the answer choices?

Answer 12

I don't but it says it's right :)

Answer 13

Ok that's great!

Answer 14

Thank you so much

Answer 15

You're welcome :)

Answer 16

Note that another way of doing this is to see that there is a \(\frac{6}{22}\) chance you get a green one, so there is a \(1-\dfrac{6}{22}=\frac{22}{22}-\frac{6}{22}=\frac{16}{22}=\frac{8}{11}\)

Sometimes this method is easier.