PLEASE HELP I'LL MEDAL
What is the average rate of change of f(x), represented by the graph, over the interval [-1, 2]?
Graph
https://cdn.ple.platoweb.com/EdAssets/ca8754551a8c4f39b660b45b8d4072f9?ts=635319036502430000
A.-2.5
B.-2
C.2.5
D.3
E.6
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (-studywith-):
Hi, do you know the average rate of change formula?
OpenStudy (jaylokss):
No can u tell me
OpenStudy (-studywith-):
Yeah, so for the interval from -1 to 2, it's A(x) = f(2) - f(-1)/ 2-(-1)
OpenStudy (-studywith-):
Do you have any functions included in the question?
OpenStudy (jaylokss):
OK so I divide f (2)-f (1)/2-(-1)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (-studywith-):
Yeah, you know what the functions are though, right? They have to tell you.
OpenStudy (jaylokss):
Nah that's all they gave me
OpenStudy (-studywith-):
No graph?
OpenStudy (jaylokss):
Wait I put a link it should take u there^
OpenStudy (-studywith-):
Ah, I see, srry i didnt notice it
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (-studywith-):
oh...
OpenStudy (jaylokss):
U know the shower tho?
OpenStudy (jaylokss):
Answer*
OpenStudy (jaylokss):
Cuz when i divide it it gave me f
OpenStudy (-studywith-):
no, not these graphs D:
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (jaylokss):
Is koo thanks anyways
OpenStudy (-studywith-):
Ask zepdrix, he's a genius
OpenStudy (-studywith-):
And online
OpenStudy (-studywith-):
;)
jimthompson5910 (jim_thompson5910):
draw a vertical line through x = -1 on the x axis
see attached
where does the red vertical line cross the function curve? at what (x,y) point?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (jaylokss):
5?
jimthompson5910 (jim_thompson5910):
I think you mean -5 and you're looking at the y coordinate it seems
OpenStudy (jaylokss):
Yeah
jimthompson5910 (jim_thompson5910):
so the point (-1,-5) is on the function curve
jimthompson5910 (jim_thompson5910):
now do the same for x = 2
where does the green line cross the function curve?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (jaylokss):
5 right
jimthompson5910 (jim_thompson5910):
look closely
jimthompson5910 (jim_thompson5910):
OpenStudy (jaylokss):
2.5
jimthompson5910 (jim_thompson5910):
yes 2.5
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
so (-1,-5) is one point on the curve. Call this point A
(2,2.5) is another point on the curve. Call this point B
find the slope of the line AB
OpenStudy (jaylokss):
-0.83?
jimthompson5910 (jim_thompson5910):
Use the slope formula
\[\Large m = \frac{y_2 - y_1}{x_2 - x_1}\]
jimthompson5910 (jim_thompson5910):
(x1,y1) = (-1,-5)
(x2,y2) = (2, 2.5)
OpenStudy (jaylokss):
-8
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
(x1,y1) = (-1,-5)
(x2,y2) = (2, 2.5)
\[\Large m = \frac{y_2 - y_1}{x_2 - x_1}\]
\[\Large m = \frac{2.5-(-5)}{2-(-1)}\]
\[\Large m = \frac{2.5+5}{2+1}\]
\[\Large m = \underline{ \ \ \ \ \ \ \ \ \ \ \ }\]
Fill in the blank. Tell me what you get.
OpenStudy (jaylokss):
2.5
jimthompson5910 (jim_thompson5910):
yep that's the slope of line AB
OpenStudy (jaylokss):
Ight thanks
jimthompson5910 (jim_thompson5910):
the slope AB is the same as the average rate of change from x = -1 to x = 2