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Mathematics 21 Online
OpenStudy (jaylokss):

PLEASE HELP I'LL MEDAL What is the average rate of change of f(x), represented by the graph, over the interval [-1, 2]? Graph https://cdn.ple.platoweb.com/EdAssets/ca8754551a8c4f39b660b45b8d4072f9?ts=635319036502430000 A.-2.5 B.-2 C.2.5 D.3 E.6

OpenStudy (-studywith-):

Hi, do you know the average rate of change formula?

OpenStudy (jaylokss):

No can u tell me

OpenStudy (-studywith-):

Yeah, so for the interval from -1 to 2, it's A(x) = f(2) - f(-1)/ 2-(-1)

OpenStudy (-studywith-):

Do you have any functions included in the question?

OpenStudy (jaylokss):

OK so I divide f (2)-f (1)/2-(-1)

OpenStudy (-studywith-):

Yeah, you know what the functions are though, right? They have to tell you.

OpenStudy (jaylokss):

Nah that's all they gave me

OpenStudy (-studywith-):

No graph?

OpenStudy (jaylokss):

Wait I put a link it should take u there^

OpenStudy (-studywith-):

Ah, I see, srry i didnt notice it

OpenStudy (-studywith-):

oh...

OpenStudy (jaylokss):

U know the shower tho?

OpenStudy (jaylokss):

Answer*

OpenStudy (jaylokss):

Cuz when i divide it it gave me f

OpenStudy (-studywith-):

no, not these graphs D:

OpenStudy (jaylokss):

Is koo thanks anyways

OpenStudy (-studywith-):

Ask zepdrix, he's a genius

OpenStudy (-studywith-):

And online

OpenStudy (-studywith-):

;)

jimthompson5910 (jim_thompson5910):

draw a vertical line through x = -1 on the x axis see attached where does the red vertical line cross the function curve? at what (x,y) point?

OpenStudy (jaylokss):

5?

jimthompson5910 (jim_thompson5910):

I think you mean -5 and you're looking at the y coordinate it seems

OpenStudy (jaylokss):

Yeah

jimthompson5910 (jim_thompson5910):

so the point (-1,-5) is on the function curve

jimthompson5910 (jim_thompson5910):

now do the same for x = 2 where does the green line cross the function curve?

OpenStudy (jaylokss):

5 right

jimthompson5910 (jim_thompson5910):

look closely

jimthompson5910 (jim_thompson5910):

OpenStudy (jaylokss):

2.5

jimthompson5910 (jim_thompson5910):

yes 2.5

jimthompson5910 (jim_thompson5910):

so (-1,-5) is one point on the curve. Call this point A (2,2.5) is another point on the curve. Call this point B find the slope of the line AB

OpenStudy (jaylokss):

-0.83?

jimthompson5910 (jim_thompson5910):

Use the slope formula \[\Large m = \frac{y_2 - y_1}{x_2 - x_1}\]

jimthompson5910 (jim_thompson5910):

(x1,y1) = (-1,-5) (x2,y2) = (2, 2.5)

OpenStudy (jaylokss):

-8

jimthompson5910 (jim_thompson5910):

(x1,y1) = (-1,-5) (x2,y2) = (2, 2.5) \[\Large m = \frac{y_2 - y_1}{x_2 - x_1}\] \[\Large m = \frac{2.5-(-5)}{2-(-1)}\] \[\Large m = \frac{2.5+5}{2+1}\] \[\Large m = \underline{ \ \ \ \ \ \ \ \ \ \ \ }\] Fill in the blank. Tell me what you get.

OpenStudy (jaylokss):

2.5

jimthompson5910 (jim_thompson5910):

yep that's the slope of line AB

OpenStudy (jaylokss):

Ight thanks

jimthompson5910 (jim_thompson5910):

the slope AB is the same as the average rate of change from x = -1 to x = 2

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