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Mathematics 7 Online
OpenStudy (kingogcobraxx):

help pls

OpenStudy (kingogcobraxx):

@guoalice8

OpenStudy (guoalice8):

what is wrong?

OpenStudy (kingogcobraxx):

OpenStudy (guoalice8):

what do u not understand about the question

OpenStudy (kingogcobraxx):

the answer

OpenStudy (guoalice8):

what do you think the answer is?

OpenStudy (kingogcobraxx):

the one clicked

OpenStudy (guoalice8):

it is c actually but do u understand how it is c

OpenStudy (kingogcobraxx):

OpenStudy (kingogcobraxx):

@Mehek14

Mehek (mehek14):

That's right.

OpenStudy (kingogcobraxx):

yay

OpenStudy (kingogcobraxx):

Mehek (mehek14):

Correct.

OpenStudy (kingogcobraxx):

Mehek (mehek14):

Any idea?

OpenStudy (kingogcobraxx):

not really

OpenStudy (kingogcobraxx):

@kittiwitti1

OpenStudy (kittiwitti1):

Make an educated guess.

OpenStudy (kittiwitti1):

separate it:\[\frac{28}{4}\times\frac{a^{-3}}{a^{1}}\]\(a\) is also \(a^{1}\) \(28\div4=\) ?\[\frac{a^{-3}}{a^{1}}\rightarrow a^{-3-1}\]

OpenStudy (kittiwitti1):

bigger version of last part:\[\LARGE{\frac{a^{-3}}{a^{1}}=a^{(-3)-1}}\]

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