A set of numbers is shown below:

{0, 0.6, 2, 4, 6}

Which of the following shows all the numbers from the set that make the inequality 2x + 3 ≥ 7 true? (1 point)

{4, 6}

{0, 0.6, 2}

{0, 0.6}

{2, 4, 6}

Question

A set of numbers is shown below:

{0, 0.6, 2, 4, 6}

Which of the following shows all the numbers from the set that make the inequality 2x + 3 ≥ 7 true? (1 point)

	
{4, 6}
 	
{0, 0.6, 2}
 	
{0, 0.6}
 	
{2, 4, 6}

zzr0ck3r · Answer

take the numbers in the set and plug them in to $2x+3\ge 7$ and if it is true, then that number will be in the solution set.

faiqraees · Answer

How about if you show us your working?

zzr0ck3r · Answer

if you plug in 0 is it true?

acespeedfighter · Answer

wait i messed up one sec

faiqraees · Answer

A little hint on what he meant
Plugging means equate x to that value 
Like if in a set there is a 1
then x = 1
2(1)+3≥7
6≥7 which is not true

acespeedfighter · Answer

its ot true 2,1+3=6

acespeedfighter · Answer

not*

faiqraees · Answer

Yes that's what I said. Try figuring out numbers for which inequality is true

acespeedfighter · Answer

I wanna say "A" but im not sure

faiqraees · Answer

Yes very good. 4 and 6 both satisfies the inequality. But there is just one number left

acespeedfighter · Answer

oh ok so it would be D wasnt checking myself

faiqraees · Answer

Yes perfect

acespeedfighter · Answer

K thx heres your medal