Question

Find the magnitude & direction of the vector JK given points J(1,0) & K(-2,3).




Select one:


a. 32 √ 32 ; 135 degrees

b. 43 √ 43 ; 140 degrees

c. 6 ; 135 degrees

d. 55 √ 55 ; 150 degrees

Answer 1

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Answer 2

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Answer 3

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Answer 4

vector JK=(-2-1,3-0)=(-3,3)
\[magnitude=\left| JK \right|=\sqrt{\left( -3 \right)^2+3^2}=\sqrt{18}=3\sqrt{2}\]

Answer 5

correction \[\tan \theta=\frac{ 3 }{ -3 }=-1\]