Question

Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?

Answer 1

I think we have to first find the slope m
do you know how to find the slope between two points, using change in y divided by change in x ?

Answer 2

I know I should but I do not, im not the most talented with math

Answer 3

J(–4, –5) and K(–6, 3)

do J-K for each number in the pair: -4 - (-6) and -5 - (3)
can you simplify those ?

Answer 4

2 and -8

Answer 5

yes, the first number is the change in x i.e. 2
the 2nd number is the change in y -8
the slope m is change in y divided by change in x
what do you get for m ?

Answer 6

you should get m= -8/2 = -4

now in
y = mx + b
replace m with -4

y = -4 x + b

to find b, use either (x,y) point
for example (-4,-5). we replace x with -4 and the y with -5:
-5 = -4*-4 + b
-4 * -4 is +16 so that simplifies to
-5 = 16+b
the last step is to add -16 to both sides
and then simplify.

Answer 7

Thank you!