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Geometry 17 Online
OpenStudy (fludge):

Need help simplifying radicals

jhonyy9 (jhonyy9):

what are these radicals ?

OpenStudy (fludge):

So, I'm pretty sure 6√3 is already simplified. But i have no idea how to solve this equation, i will attach images of what the question and answer is.

OpenStudy (fludge):

OpenStudy (fludge):

OpenStudy (fludge):

OpenStudy (fludge):

I just need help with the radicals

jhonyy9 (jhonyy9):

with what radicals please ?

jhonyy9 (jhonyy9):

you used there sqrt3 = 1,73 or what radicals are there again ?

OpenStudy (fludge):

6√3 in the problem, how does that help me solve the area of the segment? how does it find 36√3? how does it help me find the area of the triangle? (the extra pictures are showing me how to solve it, but idk what 6√3 is)

OpenStudy (fludge):

Look at picture zxcv.png where it shows the radicals

jhonyy9 (jhonyy9):

ok i understand you - so you dont now from where have got this sqrt3 - yes ?

OpenStudy (fludge):

Yes, but another thing is i have no idea what it equals to, because when i input 6√3 in a calculator, it doesn't give me the right thing i need to find the area of the segment and triangle as a whole

OpenStudy (fludge):

You get the √3 from multiplying 6 (short leg) by √3 and you get 6√3.

OpenStudy (fludge):

6√3 is the long leg of the triangle

jhonyy9 (jhonyy9):

no 6sqrt3 is the height of this triangle - the length of OX - check it please the length of long side is 12

jhonyy9 (jhonyy9):

and do you know formula for area of a triangle ?

OpenStudy (fludge):

12 is the hypotenuse of the triangle. altitude is the long leg right?

jhonyy9 (jhonyy9):

altitude is OX

OpenStudy (fludge):

Formula for area of a triangle is A=1/2 BH

jhonyy9 (jhonyy9):

yes right so B = ? and H = ?

OpenStudy (fludge):

base = 6 and height = 6√3

jhonyy9 (jhonyy9):

B = AB = ? H = OX = ?

OpenStudy (fludge):

oh, ab as a whole. 12

jhonyy9 (jhonyy9):

base not is 6 - check it please

jhonyy9 (jhonyy9):

yes exactly

OpenStudy (fludge):

So yeah, the 1/2 only applies to 12 right? Or does it go to 6√3 as well?

jhonyy9 (jhonyy9):

so area equal (1/2)(12*6sqrt3 = (72sqrt3)/2 = ?

OpenStudy (acespeedfighter):

@jhonyy9 can you help me after this question please?

OpenStudy (fludge):

Is it 31.1?

jhonyy9 (jhonyy9):

i will try it - moment please

OpenStudy (acespeedfighter):

k

jhonyy9 (jhonyy9):

how you get this result ,please ?

OpenStudy (fludge):

I accidentally put a + sign where the = was combining the problem, woops

OpenStudy (fludge):

is it 62.3?

jhonyy9 (jhonyy9):

72sqrt3 /2 = 36sqrt3 = 36*1,73 = 62,28 so you are right with this result sure

jhonyy9 (jhonyy9):

but dont forget the unit measure please

jhonyy9 (jhonyy9):

what will be ?

OpenStudy (fludge):

13cm...?

jhonyy9 (jhonyy9):

what is this 13 cm ?

OpenStudy (fludge):

Idunno what the unit measure is :c

OpenStudy (fludge):

Would it just be CM?

jhonyy9 (jhonyy9):

yes cm is the unit measure exactly

OpenStudy (fludge):

yes, and the answer to the whole question is 13cm

jhonyy9 (jhonyy9):

but you need calculi area of triangle and area of this sector of circle and subtract area of triangle from area of this sector of the circle and hence will get area of this segment hope you understand me now

jhonyy9 (jhonyy9):

ok. ?

jhonyy9 (jhonyy9):

1. area of this triangle = ?

OpenStudy (fludge):

36√3...?

jhonyy9 (jhonyy9):

yes - right 2. area of this sector of circle = ?

OpenStudy (fludge):

24pi?

jhonyy9 (jhonyy9):

how you get it ?

OpenStudy (fludge):

1/6x144/1pi

jhonyy9 (jhonyy9):

yes - bc. area of circle is 144pi and this sector is 1/6 part of area of circle so will be 24pi ok now just you need subtracting from 24pi this area of triangle yes ?

jhonyy9 (jhonyy9):

so how will be ?

OpenStudy (fludge):

yes, subracting 24pi (which is 75) by 36√3 (which is 62) will equal 13

jhonyy9 (jhonyy9):

do you understand it now sure ?

OpenStudy (fludge):

Yeah, If I reread it enough I'll start to understand it. c:

jhonyy9 (jhonyy9):

ok. hope helped you good luck bye bye

OpenStudy (fludge):

yuh, bye c:

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