Question

Precalculus question

Answer 1

For Part I, do I just plug in 0 for t? Which would give me 0 meters as the object's position?

Answer 2

Looks good so far.

Answer 3

d = 4 sin (pi t)
when t = 0
d = 4 sin (pi*0)
= 4 sin 0
= 0

Answer 4

For Part II, I have 4 meters as the maximum displacement. Correct?

Answer 5

Hint for the second part:- the maximum value for the sine is 1

Answer 6

yes correct

Answer 7

Part III, I have 2 seconds as the period.

Answer 8

how did you do that?

Answer 9

period = 2pi/omega and omega is pi in this case... lol, did I do it wrong?

Answer 10

No that is correct

Answer 11

good job

Answer 12

ok?

Answer 13

Then the frequency is 1/2, just 1 over the period right?

Answer 14

What unit would that be measured in?

Answer 15

yes

Answer 16

ms-1

Answer 17

meters per second

Answer 18

Thanks! The last part asks for the height of the jobject at t = 1.75. I just plug it in right?

Answer 19

this is Simple Harmonic Motion.

Answer 20

Yeah

Answer 21

hmm , not sure Physics is not my strong point. Plugging 1.75 will give the displacement I would have thought.

Answer 22

sorry I cant be sure about that.

Answer 23

Lol, this is precalc :P
I plugged in 1.75 and got -sqrt2/2... it doesn't seem right... hmmm :/

Answer 24

that means that the object is at the negative side of the point around which it is oscillating.

Answer 25

its starts at x = 0 then moves to the right 4 units
then reverses to point -4 and so on

Answer 26

looks about right because the period is 2 so at 1.75 it would be at negative end.

Answer 27

Hmmm okay, thanks for your help!

Answer 28

Should I write it as -sqrt2/2 or simplify it?

Answer 29

yw
leave it like that