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Mathematics 21 Online
OpenStudy (diamondanon2):

Question Below.

OpenStudy (diamondanon2):

I am doing a practice quiz, and want to go over various questions to try to understand the material better.

OpenStudy (diamondanon2):

These are the answer choices.

jhonyy9 (jhonyy9):

so Diamond how you know what is the first step ,first of all when there is or there are the unknowed terms in denominators ?

OpenStudy (diamondanon2):

I do not.

jhonyy9 (jhonyy9):

do you know when is a fraction undefined ?

OpenStudy (diamondanon2):

I do not.

jhonyy9 (jhonyy9):

can having a fraction denominator equal zero ?

OpenStudy (diamondanon2):

no

jhonyy9 (jhonyy9):

no never - bc. than will be this fraction undefined so this is the first step to made what are the restrictions for x for what the denominator result zero - ok. ?

OpenStudy (diamondanon2):

okay I see

jhonyy9 (jhonyy9):

so what will be in this case x not can being equal how many ?

jhonyy9 (jhonyy9):

make x+4 = 0 so x = ? and x-7 =0 so x = ? and these will be the restrictions for x

OpenStudy (diamondanon2):

okay

OpenStudy (diamondanon2):

-4 and 7

jhonyy9 (jhonyy9):

yes and now how you find this domain - do you know it ?

OpenStudy (diamondanon2):

I do not

jhonyy9 (jhonyy9):

above with this restrictions you get the zeros of denominator yes ? so now you need to calculi what will be the roots of numerator too do you can ?

OpenStudy (diamondanon2):

I do not know how.

jhonyy9 (jhonyy9):

what is the numerator of this fraction ?

OpenStudy (diamondanon2):

which one?

OpenStudy (diamondanon2):

or do oyu mean x(x-3)

jhonyy9 (jhonyy9):

yes this is the numerator

jhonyy9 (jhonyy9):

can you solve it now what will be the roots ?

jhonyy9 (jhonyy9):

just make it equal zero and solve it for x

OpenStudy (diamondanon2):

x= 0,3

jhonyy9 (jhonyy9):

exactly - nice

jhonyy9 (jhonyy9):

so now you know that for x = 0 and x =3 result y = 0 yes ?

OpenStudy (diamondanon2):

yes

jhonyy9 (jhonyy9):

you learned how you can finding the domain of a function ?

OpenStudy (diamondanon2):

yes

OpenStudy (diamondanon2):

so what would the answer be of the choices

OpenStudy (diamondanon2):

jhonyy9 (jhonyy9):

what you marked there is right,correct sure

OpenStudy (diamondanon2):

okay thank you very much

jhonyy9 (jhonyy9):

welcome my pleasure and anytime than i m here online just tag me and i will try help you bye bye

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