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OpenStudy (diamondanon2):
I am doing a practice quiz, and want to go over various questions to try to understand the material better.
OpenStudy (diamondanon2):
These are the answer choices.
jhonyy9 (jhonyy9):
so Diamond how you know what is the first step ,first of all when there is or there are the unknowed terms in denominators ?
OpenStudy (diamondanon2):
I do not.
jhonyy9 (jhonyy9):
do you know when is a fraction undefined ?
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OpenStudy (diamondanon2):
I do not.
jhonyy9 (jhonyy9):
can having a fraction denominator equal zero ?
OpenStudy (diamondanon2):
no
jhonyy9 (jhonyy9):
no never - bc. than will be this fraction undefined
so this is the first step to made what are the restrictions for x for what the denominator result zero - ok. ?
OpenStudy (diamondanon2):
okay I see
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jhonyy9 (jhonyy9):
so what will be in this case x not can being equal how many ?
jhonyy9 (jhonyy9):
make x+4 = 0 so x = ?
and x-7 =0 so x = ?
and these will be the restrictions for x
OpenStudy (diamondanon2):
okay
OpenStudy (diamondanon2):
-4 and 7
jhonyy9 (jhonyy9):
yes
and now how you find this domain - do you know it ?
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OpenStudy (diamondanon2):
I do not
jhonyy9 (jhonyy9):
above with this restrictions you get the zeros of denominator yes ?
so now you need to calculi what will be the roots of numerator too
do you can ?
OpenStudy (diamondanon2):
I do not know how.
jhonyy9 (jhonyy9):
what is the numerator of this fraction ?
OpenStudy (diamondanon2):
which one?
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OpenStudy (diamondanon2):
or do oyu mean x(x-3)
jhonyy9 (jhonyy9):
yes this is the numerator
jhonyy9 (jhonyy9):
can you solve it now what will be the roots ?
jhonyy9 (jhonyy9):
just make it equal zero and solve it for x
OpenStudy (diamondanon2):
x= 0,3
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jhonyy9 (jhonyy9):
exactly - nice
jhonyy9 (jhonyy9):
so now you know that for x = 0 and x =3 result y = 0 yes ?
OpenStudy (diamondanon2):
yes
jhonyy9 (jhonyy9):
you learned how you can finding the domain of a function ?
OpenStudy (diamondanon2):
yes
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OpenStudy (diamondanon2):
so what would the answer be of the choices
OpenStudy (diamondanon2):
jhonyy9 (jhonyy9):
what you marked there is right,correct sure
OpenStudy (diamondanon2):
okay thank you very much
jhonyy9 (jhonyy9):
welcome
my pleasure and anytime than i m here online just tag me and i will try help you
bye bye