Question

the height y and horizontal distance x covered by a projectile in a time t seconds are given by equations y = 8t - 5t^2 and x = 6t .If x and y are in metres ,the velocity of projection is?

Answer 1

y = 8t - 5t^2

compare this with

y = u*t - 1/2 g t^2

Answer 2

Can we say the vertical velocity, u = 8 ?

Answer 3

yes...

Answer 4

@ganeshie8

Answer 5

The horizontal motion was given by
x = 6t

Could you eyeball the horizontal velocity from above ?

Answer 6

Haha that is funny. You may use the relation :

distance = speed*time

Answer 7

You said "eyeball" so I thought youre asking me to draw a diagram haha

Answer 8

speed = 6 then?

Answer 9

Horizontal speed would be 6

Answer 10

Vertical speed = 8

Answer 11

10?

Answer 12

Find the hypotenuse to get the actual speed.

Answer 13

Yep!

Answer 14

Thanks!
Can you help me with a few more questions?