Question

What are the potential solutions to the equation below? 2In(x+3)=0

They can be:

x= -3 and x=-4

x= -2 and x=-4

x= 2 and x= -3

x= 2 and x= 4

Answer 1

\(a\log(x+b)=0\implies \log(x+b)=0\implies 10^0=x+b\implies x=1-b\)

Answer 2

ln( x + 3) = 0

what number has a logarithm of 0?

Answer 3

Thank I got the answer x= -2 and x=-4

Answer 4

yes

Answer 5

why do they ask about potential solutions?

Answer 6

So they want you to bring the exponent up, solve the quadratic and then exclude a solution. You can get around all of that by dividing the 2 away. Silly question.