MEDAL!! ALGEBRA HELP!
Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the coefficient 'k' in the factored form?
6x3 + 4x2 − 6x − 4 = 2(x + k)(x − k)(3x + 2)
k= ____________
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OpenStudy (evoker):
I would recommend dividing out the factors already given, and see what remains.
OpenStudy (bringmethehorizon_):
How do I do that? @Evoker
OpenStudy (evoker):
well basically the process is just like long division
OpenStudy (evoker):
But first taking out the 2 gives, 3x^3+2x^2-3x-2
OpenStudy (bringmethehorizon_):
So I just solve that?
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OpenStudy (evoker):
I'm working on an illustration now of the first step
OpenStudy (evoker):
|dw:1470070643272:dw|
OpenStudy (evoker):
ok here is the initial setup, so now you ask what times 3x gives 3x^3
OpenStudy (bringmethehorizon_):
9?
OpenStudy (evoker):
or to put it another way what is 3x^3/3x
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OpenStudy (evoker):
*(3x^3)/(3x)
OpenStudy (bringmethehorizon_):
I'm confused rip
OpenStudy (bringmethehorizon_):
what does 3x^3 equal
OpenStudy (evoker):
\[\frac{ 3x^3 }{3x }\]
OpenStudy (evoker):
oh sorry to answer your question 3 x^3 means 3 times x cubed.
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OpenStudy (evoker):
Have to go for a bit
OpenStudy (evoker):
so anyways that yields x^2, so you put that above the first element and then multiply x^2 times 3x+2 and put it under the equation, as shown below
OpenStudy (evoker):
|dw:1470072334590:dw|
OpenStudy (evoker):
Then you subtract
OpenStudy (evoker):
|dw:1470072392195:dw|
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OpenStudy (evoker):
Since this yields 0, we move to the next non zero term, and repeat the process.
OpenStudy (evoker):
|dw:1470072640437:dw|
OpenStudy (bringmethehorizon_):
Ohhhh that's what I kept getting and I was confused
OpenStudy (evoker):
so you are left with x^2-1
OpenStudy (evoker):
that factors into x+1 and x-1
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