Can someone help me and explain how you sloved
1.
Given e x =6.308
ex=6.308
Round to the nearest thousandths

2.
Given e x+1 =4.569
ex+1=4.569
Round to the nearest thousandths

3.
Given e 2x−1 =6.897
e2x−1=6.897
Round to the nearest thousandths

Question

Can someone help me and explain how you sloved
1.
Given e x =6.308 
ex=6.308
Round to the nearest thousandths

2.
Given e x+1 =4.569 
ex+1=4.569
Round to the nearest thousandths

3. 
Given e 2x−1 =6.897 
e2x−1=6.897
Round to the nearest thousandths

mathmate · Answer

The question posted appears to have a problem of formatting.
I assume that 
`Given e x =6.308 `
is meant to be
Given $e^x =6.308 $
and that you would like to solve for x.

Here's an example:
Given $e^x =5.472 $
take $\log_e$ on both sides, 
$\log_e  e^x = \log_e 5.472~\Rightarrow ~ x \log_e e =1.69964\Rightarrow x=1.69964$
since $\log_e e=1$ by definition of logarithm.